Lewis Diagrams and Molecular Geometry

covalent compounds, electrons are shared between atoms. Lewis structures are often used to represent
covalent bonding. Atoms in covalent compounds will form enough bonds to obtain eight electrons in
their valence shell, a property known as the octet rule. There are exceptions to the octet rule – one such
exception is called the duet rule which occurs with hydrogen (H) atoms. Because only two electrons fit
into the n = 1 shell, H atoms can have a maximum of a single bond, or 2 electrons total. There are also
atoms in compounds that form incomplete octets (less than 8 electrons) or expanded octets (more than 8
electrons).
Lewis structures typically contain shared pairs of electrons, or bonds, and lone pairs of electrons. The
number of bonds that form between atoms in a compound is directly related to the number of valence
electrons in a compound. The number of valence electrons for a compound is always equal to the total
number of valence electrons for its atoms. For a main group element, the number of valence electrons for
an atom is equal to its group number. For example, oxygen (O), is in Group VIA and has 6 valence
electrons, and Carbon (C), is in Group IVA and has 4 valence electrons. Therefore carbon monoxide
(CO) has a total of 6+4, or 10 valence electrons.
Because carbon monoxide does not contain enough valence electrons to fill both the carbon’s and the
oxygen’s valence shells separately, some of the 10 electrons will be share by both the carbon and the
oxygen. A single bond occurs between atoms, when 2 electrons are shared between two atoms, meaning
the valence shells of the two atoms overlap so the electrons can exist in the valence shell of both atoms. A
double bond occurs between two atoms when 4 electrons are shared. A triple bond occurs between two
atoms when 6 electrons are shared in a bond. Electrons that are not shared between two atoms are called
lone pair electrons. These electrons contribute to the total valence electron count for the compound. The
Lewis structures of the common compounds, ammonia, water, and hydrogen fluoride are shown in Figure
14.1 below. These structures contain only single bonds. The Lewis structures for compounds with
double and triple bonds with lone pairs are shown in Figures 14.2 and 14.3 below.
Figure 14.1 – Lewis Structures of Common Compounds containing Single Bonds
Chemistry 151
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Week 14 – Lewis Diagrams and Molecular Geometry
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Figure 14.2 – Lewis Structures of Common Compounds containing Double and Triple Bonds
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To draw the Lewis structure for a compound, follow the steps below:
1. Determine the number of valence electrons for the compound. For cations, subtract an electron for
each positive charge and for anions, add one electron for each negative charge.
2. Draw a “skeleton” structure for each molecule or ion, arranging the atoms around the central atom,
which is generally the least electronegative atom in the compound.
3. Connect each atom to the central atom with a single bond (one electron pair).
4. Distribute the remaining electrons as lone pairs on the terminal atoms, completing an octet around each
atom. (Remember that H atoms only have two electrons to fill the valence shell).
5. Place all remaining electrons on the central atom.
6. Rearrange the electrons of the outer atoms to make multiple bonds with the central atom to obtain
octets when needed.
Lewis structures simply show the linkages between atoms and the presence of lone pairs. They do not, by
themselves, show the three-dimensional arrangement of atoms in space. The Valence Shell Electron Pair
Repulsion (VSEPR) theory develops Lewis’s ideas so that we can predict the shapes of simple molecules.
The VSEPR theory adds rules that account for bond angles.
Rule 1: Regions of high electron concentration (bonds and lone pairs on the central atom) repel one
another and, to minimize the repulsions, these regions move as far as possible from each other
while maintaining the same distance from the central atom.
Rule 2: There is no distinction between single and multiple bonds: a multiple bond is treated as a single
region of high electron concentration.
Chemistry 151
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Week 14 – Lewis Diagrams and Molecular Geometry
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Rule 3: All regions of high electron concentration, lone pairs and bonds, are included in a description of
the electronic arrangement, but only the positions of atoms are considered when identifying the
shape of a molecule.
We begin by looking at molecules that consist of one central atom to which all the other atoms are
attached with no lone pairs on the central atom. (Fig. 1) The molecular shape is the same as the electron
arrangement in these molecules.
Figure 14.3 – The names of the shapes of simple molecules with no lone pairs on the central atom.
The bond angles, the angles between the bonds, are fixed by the symmetry of the molecules as shown in
Figure 14.3: linear (180O), trigonal planar (120O), and tetrahedral (109.5O). When there is more than one
central atom in a molecule, the molecular geometry can be determined on each central atom.
Now we consider molecules with one or more lone pairs on the central atom. (Figure 14.4) If lone pairs
are present, the molecular shape differs from the electron arrangement because only the positions of the
atoms are considered when naming the shape.
Figure 14.4 – The names of the shapes of some simple molecules with lone pairs (located on top of the
central atom) on the central atom.
The electrons in the molecules shown here are arranged in a tetrahedral geometry, but have a different
molecular shape. The presence of lone pairs on the central atom makes distinction between the electron
geometry and the molecular shape. To help predict the shapes of molecules, we use the generic “VSEPR
formula”: AXnEm, where A represents a central atom, X represents an attached atom, and E represents a
lone pair on the central atom.
Chemistry 151 Week 14 – Lewis Diagrams and Molecular Geometry
College of the Canyons
Page 4
Table 14.1 Molecular Shapes Predicted by VSEPR
Steric
number
(Electronic
geometry)
Molecular geometry with VSEPR formula
0 lone pair 1 lone pair 2 lone pairs
2
Linear Linear (AX2)
3
Trigonal
planar Trigonal planar
(AX3) Bent (AX2E)
4
Tetrahedral
Tetrahedral
(AX4) Trigonal Pyramid (AX3E) Bent
(AX2E2)
In covalent bonds, electrons are shared between atoms. However, the electrons in a covalent bond are not
always shared evenly. A polar covalent bond results from the uneven sharing of electrons between two
atoms, a polar covalent bond results. A polar covalent bond is characterized by a partial positive charge
(δ+) and a partial negative charge (δ-) on opposite ends of the bond. A polar molecule is a molecule that
displays a partial positive and partial negative charge on opposite ends of the molecule. Polarity of a
molecule arises from two factors: (1) the presence of a polar covalent bond within the molecule and (2)
the shape of the molecule. We can determine the polarity of a molecule in two different cases:
Case 1: A diatomic molecule*
(1) A diatomic molecule is polar if its bond is polar. (Ex) An HCl molecule: a polar molecule with its
polar covalent bond (δ+H−Clδ−).
All diatomic molecules composed of atoms of two different elements are at least slightly polar.
(2) A homonuclear diatomic molecule, a diatomic molecule built from two atoms of the same element,
such as O2, N2, and Cl2, is nonpolar, because its bond is nonpolar.
Case 2: A polyatomic molecule*
(1) A polyatomic molecule may be nonpolar even if its bonds are polar.
(a) CO2 is nonpolar: the two δ+C=Oδ− dipole moments in carbon dioxide, a linear
molecule, point an opposite direction, and so they cancel each other.
180O
120O
< 120O
109O
< 109O < 109O
180O
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Week 14 – Lewis Diagrams and Molecular Geometry
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(b) CCl4 is nonpolar: If the four atoms attached to the central atom in a tetrahedral
molecule are the same, the polar bonds cancel and the molecule is nonpolar.
(2) A polyatomic molecule may be polar if its bonds are polar and they do not cancel
each other.
(a) H2O is polar: the two δ+H−Oδ− dipole moments in H2O lie at 104.5O to each other
and do not cancel. This polarity explains why water is such a good solvent for ionic
compounds.
(b) Both CHCl3 and NH3 are polar: If one or more of the atoms are replaced by
different atoms (as in CHCl3) or by lone pairs (as in NH3), then the polarity associated with
the bonds are not the same, so they do not cancel.
< 109O
*Lone pairs on terminal atoms are not shown in the VSEPR structures, because they are not included
when identifying molecular shapes.
PROCEDURE
1. Fill in the Data Table (total valence electrons and Lewis Diagram) for each of the compounds
in the table.
2. Assign the VSEPR electron geometry.
3. Assign the VSEPR molecular geometry (shape). Identify the shape considering only atoms.
4. Determine if there are polar bonds, and if polar bonds cancel.
a. If all the covalent bonds are non-polar bonds (i.e. if the electronegativity difference
between the two atoms is equal to or less than 0.4), the molecule is non-polar.
b. C-H bond is considered as non-polar.
c. If di-atomic molecule has a polar bond, the molecule is polar.
d. If a molecule consists of more than two atoms, consider the shape of the molecule
and bond dipoles (direction and magnitude) to see if all dipole are canceled. If those
are canceled, the molecule is non-polar. If the dipoles do not cancel and resulting a
net dipole, the molecule is polar.
Supplemental Website for Simulations:
Molecular Shape: https://phet.colorado.edu/sims/html/molecule-shapes/latest/molecule-shapes_en.html
Molecular Polarity: https://phet.colorado.edu/sims/html/molecule-polarity/latest/molecule-polarity_en.html
Chemistry 151
College of the Canyons
Week 14 – Lewis Diagrams and Molecular Geometry
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PRE-LABORATORY ASSIGNMENT
1. The VSEPR model extends Lewis’s theory to account for molecular shapes. Write the rules of the
VSEPR model that account for molecular shapes and bond angles:
a) Rule 1
b) Rule 2
c) Rule 3
2. The VSEPR formula, AXnEm, helps us to predict the molecular shape. What does each symbol
represent in the formula?
a) A:
b) X:
c) E:
3. Select a molecule in which the molecular shape is the same with the electron arrangement.
Explain your reasoning.
a) CO2 (b) H2O (c) NH3 (d) SO2
4. Select a nonpolar molecule in which the dipole moment of polar covalent bonds cancels each other.
Explain your reasoning.
(a) H2O (b) NH3 (c) CCl4 (d) HCl
Chemistry 151
College of the Canyons Week 14 – Lewis Diagrams and Molecular Geometry
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DATA TABLE
Lewis Structure and Electron Geometries
Formula
Total
Valence
Electrons
Lewis Diagram Electron
Geometry
Molecular
Geometry Polar or Not?
BF3
Note: Boron (B) is an exception to
the octet rule, which tends to have
6 valence electrons.
CHO2

SO2
NO3

O2
Chemistry 151
College of the Canyons Week 14 – Lewis Diagrams and Molecular Geometry
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Formula
Total
Valence
Electrons
Lewis Diagram Electron
Geometry
Molecular
Geometry Polar or Not?
HCOH
(C is the
central
atom)
SeO2
NH3
CCl4
H2O
Chemistry 151
College of the Canyons Week 14 – Lewis Diagrams and Molecular Geometry
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Formula
Total
Valence
Electrons
Lewis Diagram Electron
Geometry
Molecular
Geometry Polar or Not?
SiH4
HCCH
NF3
OF2
HCN
Chemistry 151
College of the Canyons
Week 14 – Lewis Diagrams and Molecular Geometry
Page 10
POST-LABORATORY QUESTIONS
1. Among molecules with 3 or more atoms, which of the molecules in your Data Sheet have the
molecular shape different from the electron group arrangement around the central atom?
List all molecules (there are six of them). What is the common feature among
those molecules?
2. CCl4 is a nonpolar molecule, while CHCl3 and CH2Cl2 are polar molecules. Draw the
Lewis structures of these three molecules. Explain the observation in polarity of the
molecules.
3. Define resonance. Which of the covalent compounds from today’s experiments show
resonance (there are four comounds). Draw all of the resonance structures for the compound.

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